圆x^2+y^2+2x-4y+1=0,即(x+1)^2+(y-2)^2=4,圆的半径为2
截得的弦长为4等于直径,所以直线过圆心.
圆心坐标为(-1,2)代入直线方程得:你的题目错了,自己改下题目,接着这样的思维做下去就ok了
如果还有什么问题就hi我吧
2ax-by+2=0(a>0,b>0).被圆x^2+y^2+2x+-4y+1=0截得的弦长为4.则1/a+1/b的最小值是
2ax-by+2=0(a>0,b>0).被圆x^2+y^2+2x+-4y+1=0截得的弦长为4.则1/a+1/b的最小值是
数学人气:468 ℃时间:2019-11-14 03:51:18
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