因式分解：x²-2xy-3y²+2x+10y-8

x^2-2xy-3y^2+2x+10y-8 =x^2+2(1-y)x-3y^2+10y-8 =x^2+2(1-y)x+(1-y)^2-(1-y)^2-3y^2+10y-8 =[x+(1-y)]^2-4y^2+12y-9 =[x+(1-y)]^2-(2y-3)^2 =[x+(1-y)-(2y-3)]*[x+(1-y)+(2y-3)] =(X-3Y+4)(X+Y-2) ^表示次方^2表示...