已知x1,x2是一元二次方程3x*x+2x-6=0的两个根,不解方程,求x1*x1+x1x2+x2*x2和x2/x1+x1/x2的值

利用两根和 、两根积公式得
x1+x2=-2/3,x1x2=-6/3=-2
x1*x1+x1x2+x2*x2
=x1*x1+2x1x2+x2*x2-x1x2
=(x1+x2)^2-x1x2
=(-2/3)^2+2
=22/9
x2/x1+x1/x2
=(x1*x1+x2*x2)/x1x2
=(x1*x1+2x1x2+x2*x2-2x1x2)/x1x2
=[(x1+x2)^2-2x1x2]/x1x2
=[(-2/3)^2+2*2]/(-2)
=-20/9