一般的,如果函数f(x)的图像关于点(a,b)对称,那么对定义域内的任意x,则f(x)+f(2a-x)=2b恒成立

(1) a = 1/2,f(2a - x) = f(1-x) = 4^(1-x)/[4^(1-x) + m]= 4/(4 +m*4^x)b = 1/2,f(x) + f(2a -x) = 1 = 4^x/(4^x+ m) + 4/(4 +m*4^x)= (4^x + m-m)/(4^x+ m) + 4/(4 +m*4^x)= 1 - m/(4^x+ m) + 4/(4 +m*4^x)m/(4^x+...