(1+2分之1)(1+2的平方分之1)+···+(1+2的16次幂分之1)
=(1-1/2)(1+2分之1)(1+2的平方分之1)+···+(1+2的16次幂分之1)/(1-1/2)
=(1-1/2^32)*2
=2-1/2^31
(1+2分之1)(1+2的平方分之1)+···+(1+2的16次幂分之1)
(1+2分之1)(1+2的平方分之1)+···+(1+2的16次幂分之1)
数学人气:917 ℃时间:2019-10-19 17:59:46
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