已知:|ab-2|+|b-1|=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(a+2)+……+1/(a+2005)(b+2005)的值 做得好提高悬赏

已知|ab-2|+|b-1|=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2005）(b+2005)|ab-2|+|b-1|=0,ab-2=0,b-1=0b=1,a=2原式=1/(1*2)+1/(2*3)+1/(3*4)+……+1/(2006*2007)因为1/(n-1)-1/n=(n-(n-1))/((n-1)*n)=1/((n-1...