已知集合A={x丨x的平方+px+q=X},B={X丨(X-1)的平方
已知集合A={x丨x的平方+px+q=X},B={X丨(X-1)的平方
B={X丨(X-1)的平方+p(x-1)+q=x+1}当A={2}时,求B
B={X丨(X-1)的平方+p(x-1)+q=x+1}当A={2}时,求B
数学人气:195 ℃时间:2019-10-31 12:53:16
优质解答
A={2},则 2^2+2p+q=2,2p+q+2=0,q=-2(p+1)x^2+px+q=x,x^2+(p-1)x+q=0上述方和只有一个解,(p-1)^2-4q=0p^2-2p+1-4*((-2(p+1))=0p^2-2p+1+8p+8=0p^2+6p+9=0p=-3,q=-2(-3+1)=4所以 B={x|(x-1)^2-3(x-1)+4=x+1}(x-1)^2-...
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