已知函数f(x)=2sin²x+2sinxcosx （1）求该函数的最小正周期 （2）求该函数的最大值和此时x的值
已知函数f(x)=2sin²x+2sinxcosx （1）求该函数的最小正周期 （2）求该函数的最大值和此时x的值
不然看不懂啦..
不然看不懂啦..
数学人气：761 ℃时间：2019-10-11 09:33:35
优质解答
解f(x)=2sin²x+2sinxcosx=2sinxcosx-(1-2sin²x)+1=sin2x-cos2x+1=√2(√2/2sin2x-√2/2cos2x)+1=√2(sin2xcosπ/4-cos2xsinπ/4)+1=√2sin(2x-π/4)+1∴最小正周期为：T=2π/2=π∵sin(2x-π/4)∈[-1.1]∴...
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