x/2=y/3
x=2y/3
所以
x²-2xy-3y²/x²-6xy-7y²
=(x+y)(x-3y)/(x+y)(x-7y)
=(x-3y)/(x-7y)
=(2y/3-3y)/(2y/3-7y)
=(2-9)/(2-21)
=7/19
已知x/2=y/3(xy≠0),求x²-2xy-3y²/x²-6xy-7y²的值
已知x/2=y/3(xy≠0),求x²-2xy-3y²/x²-6xy-7y²的值
数学人气:764 ℃时间:2019-08-20 08:56:56
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