1/（x-2)（x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
=1/(x-3)-1/(x-2)-[1/(x-3)-1/(x-1)]+1/(x-2)-1/(x-1)
=1/(x-3)-1/(x-2)-1/(x-3)+1/(x-1)+1/(x-2)-1/(x-1)
=0
利用1/n*(n+1) = 1/n - 1/(n+1)计算1/（x-2)（x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
利用1/n*(n+1) = 1/n - 1/(n+1)计算1/（x-2)（x-3)-2/(x-1)(x-3)+1/(x-1)(x-2)
数学人气：101 ℃时间：2020-05-19 16:37:33
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