已知(3x-2)²+|2x-y-3|=0,求5(2x-y)-2(6x-2y+2)+(4x-3y-2分之一)的值

(3x-2)²+|2x-y-3|=0,则 3x-2=0,x=2/3；2x-y-3=0,y=2x-3=4/3-3= -5/35(2x-y)-2(6x-2y+2)+(4x-3y-2分之一)=10x-5y-12x+4y-4+4x-3y-1/2=2x-4y-4-1/2=4/3+20/3-4-1/2=24/3-4-1/2=8-4-1/2=4-1/2=7/2