首先要满足定义域的要求:
x>0
2x-3>0
得:x>3/2
然后f(x)递增,则:f(x)>f(2x-3)
得:x>2x-3
x
f(x)是定义域(0,正无穷)上的增函数,则不等式f(x)>f(2x-3)的解集是
f(x)是定义域(0,正无穷)上的增函数,则不等式f(x)>f(2x-3)的解集是
数学人气:256 ℃时间:2020-06-15 10:00:37
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