定积分:(1) lim(x→a) 1/(x-a) ∫[a,x] f(t)dt
定积分:(1) lim(x→a) 1/(x-a) ∫[a,x] f(t)dt
(2) lim(x→∞) ∫[x,x+1] (sint)/t dt
(2) lim(x→∞) ∫[x,x+1] (sint)/t dt
数学人气:119 ℃时间:2020-01-27 03:02:41
优质解答
1根据洛笔答法则,=lim(x→a) f(x) =f(a)2根据积分中值定理,∫[x,x+1] (sint)/t dt=[(sinξ)/ξ]·[(x+1)-x]=(sinξ)/ξ其中ξ是介于 x和x+1之间的一个实数.当x→∞时,x+1→∞;根据夹逼原理,ξ→∞.则原极限=lim(ξ...
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