a²+b²+ab+1=a-b
2a²+2b²+2ab+2-2a+2b=0
a²-2a+1+b²+2b+1+a²+b²+2ab=0
(a-1)²+(b+1)²+(a+b)²=0
平方项恒非负,三个平方项之和=0,三个平方项都=0
a-1=0 b+1=0 a+b=0
解得a=1 b=-1
2a-b=2-(-1)=3
实数a,b满足a²+b²+ab+1=a-b 则2a-b=
实数a,b满足a²+b²+ab+1=a-b 则2a-b=
数学人气：356 ℃时间：2019-11-12 00:57:26
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