Y'=(SINX^cosX+COSX^sinx)'
=(SINX^cosX)'+(COSX^sinX)'
令y1=sinx^cosx,y2=cosx^sinx
lny1=cosxlnsinx
y1'/y1=-sinxlnsinx+cos^2x/sinx
y1'=(-sinxlnsinx+cos^2x/sinx)*sinx^cosx
同理y2'=(cosxlncosx-sin^2x/cosx)*cosx^sinx
所以y'=(-sinxlnsinx+cos^2x/sinx)*sinx^cosx+(cosxlncosx-sin^2x/cosx)*cosx^sinx
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