设函数fx=6cos平方x-2根号3sinxcosx.求fx的最小正周期和值域

f(x)=6(cosx)^2-2√3sinxcosx=6*(cos2x+1)/2-√3sin2x=3cos2x-√3sin2x+3=2√3(√3/2cos2x-1/2sin2x)+3=2√3sin(π/3-2x)+3=-2√3sin(2x-π/3)+3所以f(x)的最大值是2√3+3,最小正周期是π.若锐角α满足f（α）=3-2√...