=4.575+13.25-7.13
=17.825-7.13
=10.695;
②
1 |
20043−2003×(20042+2005) |
=
1 |
20042×2004−2003×20042−2003×2005 |
=
1 |
20042×(2004−2003)−2003×2005 |
=
1 |
20042−2003×2005 |
=
1 |
20042−2003×(2004+1) |
=
1 |
20042−2003×2004−2003 |
=
1 |
2004×(2004−2003)−2003 |
=
1 |
2004−2003 |
=1.
故答案为:10.695,1.