5x²-6x+k=0
x²-6/5x+k/5=0
x²-6/5x+9/25-9/25+k/5=0
(x-3/5)²=9/25-k/5
9/25-k/5≥0 有实数解
所以 k/5≤9/25
k≤9/5
将方程5x的2次方-6x+k=0化为(x+a)的2次方=b,并且指出k为何值时方程有实数解
将方程5x的2次方-6x+k=0化为(x+a)的2次方=b,并且指出k为何值时方程有实数解
数学人气:687 ℃时间:2020-03-31 10:40:54
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