1、x=2
2、1
3、原式=x/(x+1)(x-1)×(x-1)/(x-2)
=x/(x+1)(x-2)
=x/(x²-x-2)
4、两边乘以(x+1)(x-1)得
2x+2=4
x=1
检验:x=1是增根
∴方程无解
5、原式=x/(x-y)²×(x+y)(x-y)/(x+y)+2x+2/(x-y)-2
=x/(x-y)+(2x+2)/(x-y)-2(x-y)/(x-y)
=(x+2x+2-2x+2y)/(x-y)
=(x+2y+2)/(x-y)
∵x+2y=3 x-y=2
∴原式=(3+2)/2=5/2
1.当x=_____时,分式|x|-2/x-2无意义.2.化简:2a/a-b+a+b/b-a=_____
1.当x=_____时,分式|x|-2/x-2无意义.2.化简:2a/a-b+a+b/b-a=_____
化简:1.x/x²-1(x-1/(x)-2)
解方程:1.2/x-1=4/x²-1
先化简,再求值:x/(x-y)²×x²-y²/(x+y)+2x+2/(x-y)-2其中x,y满足方程组x+2y=3,x-y=2
化简:1.x/x²-1(x-1/(x)-2)
解方程:1.2/x-1=4/x²-1
先化简,再求值:x/(x-y)²×x²-y²/(x+y)+2x+2/(x-y)-2其中x,y满足方程组x+2y=3,x-y=2
数学人气:467 ℃时间:2020-06-05 05:00:49
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