上x1+x2+x3+4x4-3x5=0 中2x1+x2+3x3+5x4-5x5=0 中x1-x2+3x3-2x4-x5=0 下3x1+x2+5x3+6x4-7x5=0

x1+x2+x3+4x4-3x5=02x1+x2+3x3+5x4-5x5=0x1-x2+3x3-2x4-x5=03x1+x2+5x3+6x4-7x5=0（1 1 1 4 -32 1 3 5 -51 -1 3 -2 -13 1 5 6 -7）（1 1 1 4 -30 -1 1 -3 10 -2 2 -6 20 -2 2 -6 2）（1 1 1 4 -30 1 -1 3 -10 0 0 0 ...x4= x4x5=x5？我为了通解好写，作的处理，你也可以这样做： 取x3=1,x4=0,x5=0,得一特解(-2,1,1,0,0)取x3=0,x4=1,x5=0,得一特解(-1,-3,0,1,0) 取x3=0,x4=0,x5=1,得一特解(2,1,0,0,1)然后得通x=c1(-2,1,1,0,0)+c2(-1,-3,0,1,0)+c3(2,1,0,0,1)