解析
x=acost+atsint
y=asint-atcost
dx=-asint+asint+atcost
dy=acost-acost+atsint
∴dy/dx=(acost-acost+asint)/(atcost)
=asint/atcost
=tan/t
果断打字,
x=a(cost+tsint) y=a(sint—tcost) 求导dy/dx
x=a(cost+tsint) y=a(sint—tcost) 求导dy/dx
哪个大神教教我呀
哪个大神教教我呀
数学人气:184 ℃时间:2019-08-19 10:46:48
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