N=mg=50*1=500N
200cm²=0.02m²
P=F/S=N/S=500/（2*0.02）=12500Pa
某中学生质量为50kg,每只脚与水平地面接触面积为200cm².双脚站立时,他对水平地面的压力是
某中学生质量为50kg,每只脚与水平地面接触面积为200cm².双脚站立时,他对水平地面的压力是
(10N/kg), 压强是（ ）Pa要过程!
(10N/kg), 压强是（ ）Pa要过程!
物理人气：609 ℃时间：2019-08-20 15:42:34
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