(2cosα²-1/cos²α+tan²α)/(2tan(π/4-α)sin(π/4+α))²
=(2cosα²-1-tan²α+tan²α)/(2*sin(π/4-α)*sin(π/4+α))
=cos2α/cos2α
=1
化简(2cosα^2-1/cosα^2+tanα^2)/(2tan(π/4-α)sin(π/4+α)^2
化简(2cosα^2-1/cosα^2+tanα^2)/(2tan(π/4-α)sin(π/4+α)^2
数学人气：724 ℃时间：2020-02-06 05:18:54
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