用-x代替x带入原式
把f(sinx)和f(-sinx)当做两个未知数解2元二次方程
2f(sinx)+3f(-sinx)=-4sinxcosx
2f(-sinx)+3f(sinx)=4sinxcosx
乘系数相减把f(-sinx)约下去,得到f(sinx)的关系式,接下来就会解了吧(cosx^2+sinx^2=1)
若f(x)满足2f(-sin x)+3f(sin x)=4sin xcos x(x大于等于负的二分之派,小于等于二分之派).求f(x).
若f(x)满足2f(-sin x)+3f(sin x)=4sin xcos x(x大于等于负的二分之派,小于等于二分之派).求f(x).
数学人气:307 ℃时间:2020-04-10 16:59:37
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