[(3-1)×2+1]×
3 |
3+7 |
=[2×2+1]×
3 |
3+7 |
=5×
3 |
10 |
=1
5 |
10 |
第四次相遇甲跑了:
[(4-1)×2+1]×
3 |
3+7 |
=[3×2+1]×
3 |
10 |
=7×
3 |
10 |
=2
1 |
10 |
所以全程是:
150÷[(1
5 |
10 |
1 |
10 |
=150÷(
5 |
10 |
1 |
10 |
=150÷
2 |
5 |
=375(米).
答:全程为375米.
故答案为:375.
3 |
3+7 |
3 |
3+7 |
3 |
10 |
5 |
10 |
3 |
3+7 |
3 |
10 |
3 |
10 |
1 |
10 |
5 |
10 |
1 |
10 |
5 |
10 |
1 |
10 |
2 |
5 |