(√3)÷[1/(√3)]+1/(√2)]
=(√3)÷[(√3)/3+(√2)/2]
=(√3)÷[(2√3+3√2)/6]
=(√3)×[6/(2√3+3√2)]
=(√3)×[6(2√3-3√2)/(-6)]
=(√3)×(3√2-2√3)
=3(√6)-6
计算根号3除以【根号3分之一加根号2分之1】的结果是
计算根号3除以【根号3分之一加根号2分之1】的结果是
数学人气:418 ℃时间:2019-09-29 04:15:52
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