α属于(π,2π)
α/2属于(π/2,π)
sin α/2>0,cos α/2<0
根号下(1-sinα)+根号下((1+cosα)/2)
=根号[sin^2(α/2)-2sin(α/2)cos(α/2)+cos^2(α/2)]+根号{[1+2cos^2(α/2)-1]/2}
=根号[(sin(α/2)-cos(α/2))^2]+根号[cos^2(α/2)]
=|sinα/2-cosα/2|+|cosα/2|
=sin(α/2)-cos(α/2)-cos(α/2)
=sin(α/2)-2cos(α/2)
化简:根号下(1-sinα)+根号下((1+cosα)/2)
化简:根号下(1-sinα)+根号下((1+cosα)/2)
α属于(π,2π)
α属于(π,2π)
数学人气:233 ℃时间:2019-10-31 15:33:54
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