分解出来 可以这样 |4x＋5|-|x－3|0,（x>-5/4）时 去绝对值符号,得
4x＋5-[-(x-3)]-5/4时,x－33时 去绝对值符号,得
4x＋5-x+33时,4x＋5直接就大于0 就不变.
化简得x3 求交集,为空集.
还有两种自己求一下
4x＋5
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