已知抛物线y=-2x2+bx+c的顶点坐标为(1,2),求b,c的值,并写出函数的解析式.
已知抛物线y=-2x2+bx+c的顶点坐标为(1,2),求b,c的值,并写出函数的解析式.
数学人气:302 ℃时间:2019-08-20 13:45:42
优质解答
∵抛物线y=-2x
2+bx+c的顶点坐标为(1,2),
∴-
=1,
解得b=4,
当x=1时,-2+4+c=2,
解得c=0,
所以,函数解析式为y=-2x
2+4x.
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