高一三角函数化简 sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α))
高一三角函数化简 sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α))
数学人气:386 ℃时间:2019-09-29 00:25:37
优质解答
sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α)) = sin^2(α)/((sinα)-(cosα))+(cosα)/(1-sin(α)/cos(α)) =sin^2(α)/((sinα)-(cosα))+cos^2(α)/(cos(α)-sin(α)) =(sin^2(α)-cos^2(α))/((sinα)-(cosα)) =((sinα)-(cosα))((sinα)+(cosα))/((sinα)-(cosα)) =sinα+cosα
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