证明：
连接DE
∵AD是高
∴⊿ABD是Rt⊿
∵E是AB的中点,即DE为Rt⊿ABD斜边中线
∴DE=½AB=BE
∴∠B=∠EDB
∵∠B=2∠BCE
∠EDB=∠BCE+∠DEC
∴∠BCE=∠DEC
∴DC=DE=BE
已知在△ABC中,AD是高,CE是AB边上的中线,且∠ABC=2∠BCE,求证DC=BE
已知在△ABC中,AD是高,CE是AB边上的中线,且∠ABC=2∠BCE,求证DC=BE
数学人气：842 ℃时间：2019-09-30 07:27:18
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