已知x=(√3+√2)/(√3-√2),y=(√3-√2)/(√3+√2),则代数式x²-3xy+y²

x=(√3+√2)/(√3-√2)=（√3+√2）²/（3-2）=（3+2√6+2）/1=5+2√6
y=(√3-√2)/(√3+√2))=（√3-√2）²/（3-2）=（3-2√6+2）/1=5-2√6
xy=(√3+√2)/(√3-√2)* (√3-√2)/(√3+√2)=1
x²-3xy+y²
=(x²+2xy+y²)-5xy
=(x+y)²-5*1
=(5+2√6+5-2√6)²-5
=10²-5
=95