[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π] =[tan(1/4)π+tan(5/12)π]/[1-tan(1/4)πtan(5/12)π]
=tan[(1/4)π+(5/12)π]=tan(2/3π)=-tan(1/3π)=-根号3
化简：[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]
化简：[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π]
数学人气：863 ℃时间：2020-03-25 19:27:32
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