化简 tan((π/12)+1)/((π/12)-1) 求指导,

题目有误
可能是
[ tan(π/12) +1 ] / [ tan(π/12) - 1 ]
= [ tan(π/12) + tan(π/4) ] / [ tan(π/12)*tan(π/4) - 1 ]
= - tan(π/12 + π/4)
= - tan(π/3)
= - √3