楼主,
由因式定理得,x=1
∴原式=(x⁴-x³)-(3x²-3x)-(2x-2)
=x³(x-1)-3x(x-1)-2(x-1)
=(x³-3x-2)(x-1)
=[(x³-x²)+(x²-x)-(2x-2)](x-1)
=[x²(x-1)+x(x-1)-2(x-1)](x-1)
=(x²+x-2)(x-1)²
=(x+2)(x-1)³
x^4-x^3-3x^2+5x-2求详细因式分解(用因式定理)谢了
x^4-x^3-3x^2+5x-2求详细因式分解(用因式定理)谢了
数学人气:603 ℃时间:2020-02-03 08:51:25
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