己知三角形ABC中,SinA+COSA=√2/2,则tanA
己知三角形ABC中,SinA+COSA=√2/2,则tanA
数学人气：613 ℃时间：2019-09-09 17:47:07
优质解答
sinA^2+cosA^2=1 sinA+cosA=√2/2.(1) (sinA+cosA)^2=1+2sinAcosA=1/2 得2sinAcosA=-1/2 所以(sinA-cosA)^2=1-2sinAcosA=3/2 得sinA-cosA=√6/2.(2) 由（1),(2）得sinA=（√6+√2)/4 cosA=(√2-√6)/4 所以tanA=sinA/cosA=-(2+√3)好累得采一下吧
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