若α为第三象限的角,cosα=2m^2-3/3-m,求m的取值范围

因为α为第三象限的角所以-1＜cosα＜0所以-1＜(2m^2-3)/(3-m)＜0解左边：-1＜(2m^2-3)/(3-m)(2m^2-m)/(3-m)＞0m(2m-1)(m-3)＜0所以m＜0或1/2＜m＜3解右边：(2m^2-3)/(3-m)＜0(2m^2-3)(m-3)＞0(m+√6/2)(m-√6/2)(m-...