令z=x+yi,则w=z+1/z=x+yi+(x-yi)/√(x²+y²)=[x+x/√(x²+y²)]+[y-y/√(x²+y²)]i
因为w是实数且-1
设z是虚数,w=z+(1/z)是实数,且-1
设z是虚数,w=z+(1/z)是实数,且-1
u=(1-Z)/(1+Z)
u=(1-Z)/(1+Z)
数学人气：824 ℃时间：2020-01-26 05:03:09
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