设角ABC=7k
角ABD=3.5k
角ABE=2k
角DBE=角ABD-角ABE=24°=1.5k
k=16
所以角ABC=7*16°=112°
BD平分角ABC,BE分角ABC成2：5两部分,角DBE=24°,求角ABC的度数
BD平分角ABC,BE分角ABC成2：5两部分,角DBE=24°,求角ABC的度数
数学人气：124 ℃时间：2019-08-20 01:33:51
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