如果函数f(x)=(x+a)^3对任意t都有f(1+t)=-f(1-t),则f(2)+f(-2)=
如果函数f(x)=(x+a)^3对任意t都有f(1+t)=-f(1-t),则f(2)+f(-2)=
数学人气:626 ℃时间:2020-06-14 16:39:06
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f(x)=(x+a)^3f(1+t)=-f(1-t)令x=1+t 则t=x-1有f(x)=-f(1-x+1)=-f(2-x)则f(2)=-f(0)f(-2)=-f(4)f(2)=(2+a)^3=-f(0)=-a^3 推出 2+a=-a,a=-1所以f(x)=(x-1)^3则f(2)=1 f(-2)=-27f(2)+f(-2)=-26
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