复数Z=a+bi是方程Z
复数Z=a+bi是方程Z
复数Z=a+bi是方程Z(平方)=-3+4i的一个根,则z=
复数Z=a+bi是方程Z(平方)=-3+4i的一个根,则z=
数学人气:781 ℃时间:2020-02-05 07:44:34
优质解答
应该a和b是实数z²=a²-b²+2abi=-3+4ia²-b²=-32ab=4b=2/a则a²-4/a²+3=0a^4-3a²-4=0(a²-4)(a²+1)=0所以a²=4a=±2b=2/a所以z=-2-i或z=2+i
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