sinx的3次方乘以cosx的5次方的积开根号的倒数的微分是什么?

d{[(sinx)^3*(cosx)^5]^(-1/2)}
=(-1/2)[(sinx)^3*(cosx)^5]^(-3/2)*[3(sinx)^2*cosx*(cosx)^5-(sinx)^3*5(cosx)^4*sinx]dx
=(-1/2)[(sinx)^3*(cosx)^5]^(-3/2)*[3(sinx)^2*(cosx)^6-5(sinx)^4*(cosx)^4]dx
因为是求微分,所以后面加了dx