4x²-9y²=31
(2x+3y)(2x-3y)=31=31×1
2x+3y=31
2x-3y=1
相加,得
4x=32
x=8
相减,得
6y=30
y=5
即
x=8,y=5
求满足方程4x的平方减9y的平方等于31的正整数解!
求满足方程4x的平方减9y的平方等于31的正整数解!
数学人气:282 ℃时间:2019-12-22 17:19:57
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