y=√2sin(2x+π/4)+2
(1)求函数的最小正周期T=π单调递增区间 2kπ-π/2
已知函数y=根号2sin(2x+π/4)+2.(1)求函数的最小正周期及单调递增区间(2)函数的图象可由y=sinx的图像
已知函数y=根号2sin(2x+π/4)+2.(1)求函数的最小正周期及单调递增区间(2)函数的图象可由y=sinx的图像
数学人气:629 ℃时间:2019-11-24 01:47:45
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