复数方程z^6=1怎么解,求过程（有4个复数解）

如果你学过棣莫佛定理,则可以直接出答案(6个根在单位圆上均匀分布)z1=cos0+isin0=1z2=cos(π/3)+isin(π/3)=(1/2)+(√3/2)iz3=cos(2π/3)+isin(2π/3)=(-1/2)+(√3/2)iz4=cosπ+isinπ=-1z5=cos(4π/3)+isin(4π/3)=...