|a+b+2|与(2ab-1)的2次方互为相反数,求代数式(a+b)的平方除以3ab-3ab除以a+b+1的值
|a+b+2|与(2ab-1)的2次方互为相反数,求代数式(a+b)的平方除以3ab-3ab除以a+b+1的值
数学人气:586 ℃时间:2019-08-21 10:07:52
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13688461429hh,|a+b+2|与(2ab-1)²互为相反数,所以有:a+b+2=0,则a+b=-22ab-1=0,则ab=1/2(a+b)²/3ab-3ab/(a+b+1)=(-2)²/(3×1/2)-(3×1/2)/(-2+1)=4/1.5-1.5/...
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