已知函数f（x）=2cos2ωx+2sinωxcosωx+1（x∈R,ω＞0）的最小值正周期是π／2.

f(x) = 2cos2wx + sin2wx + 1 = sqrt(5) sin(2wx+A) + 1
A = arctan 2
cos A = sqrt(5)/5,sin A = 2sqrt(5)/5
f(x) 最小值正周期是π／2,所以w = 2
y = f（x+φ）为偶函数
y = cos(4x) + 1
so 4φ + A = pi/2
φ = pi/8 - arctan2 / 4