(1四次方+1/4)(3四次方+1/4)..(19四次方+1/4)/(2四次方+1/4)(4四次方+1/4)...(20四次方+1/4)
(1四次方+1/4)(3四次方+1/4)..(19四次方+1/4)/(2四次方+1/4)(4四次方+1/4)...(20四次方+1/4)
数学人气:881 ℃时间:2019-08-18 08:54:03
优质解答
答案应为 1/841首先原式化为(4x1四次方+1)(4x3四次方+1)..(4x19四次方+1)/(4x2四次方+1)(4x4四次方+1)...(4x20四次方+1)按照a^2+b^2=(a+b)^2-2ab分解因式4x(2n-1)^4+1=[2x(2n-1)^2+1]^2-4x(2n-1)^2=[2x(2n-1)^2+1+2x...
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