1.若tana=根号2,求(1)(sina+cosa)/(cosa-sina)的值 (2)2sin^2a-sinacosa+cos^2a的值
1.若tana=根号2,求(1)(sina+cosa)/(cosa-sina)的值 (2)2sin^2a-sinacosa+cos^2a的值
2.化简(sin^2atana+cos^2a/tana+2sinacosa)sinacosa
2.化简(sin^2atana+cos^2a/tana+2sinacosa)sinacosa
数学人气:357 ℃时间:2019-10-24 03:36:31
优质解答
1)(sina+cosa)/(cosa-sina)= (tana-1)/(1-tana)(同时除以cosa)=1/-1=-12)2sin^2a-sinacosa+cos^2a=(2sin^2a-sinacosa+cos^2a)/(sin^2a+cos^2a)同时除以cos^2a=(2tan^2a-tana+1)/(tan^2a+1)=(8-2+1)/5=7/53)(sin...
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