原式=lim(x→π/2) (1+sinx-1)^{[1/(sinx-1)](tanx)(sinx-1)}
=lim(x→π/2) e^[(tanx)(sinx-1)]
=e^ lim(x→π/2) (sinx-1)/cotx
=e^ lim(x→π/2) cosx/(- csc²x)
=e^0
=1
Sinx的tanx次方当x趋近于二分之派时的极限是多少啊?
Sinx的tanx次方当x趋近于二分之派时的极限是多少啊?
数学人气:385 ℃时间:2020-03-25 04:44:37
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